Titration question?How many milliliters of 0
How many milliliters of 0.01 M KmnO4 solution will required to completely titrate 0.2350 moles of oxalate ions?
The reaction between MnO4- and C2O4 2- is
2MnO4?(aq) + 5C2O42?(aq) + 16H+(aq) → 2Mn2+(aq) + 10CO2(g) + 8H2O(l)
The balanced equation tells us that 2 moles of MnO4- will react with 5 moles of C2O4 2-.
0.2350 moles C2O4 2- x (2 moles MnO4- / 5 moles C2O4 2-) = 0.0940 moles MnO4-
moles MnO4- = M MnO4- x L MnO4-
0.0940 = (0.01)(L MnO4-)
L MnO4- = 9.4 L = 9400 mL!