sinh2x = (cosh2x - 1)/2
int of (cosh2x - 1)/2 dx = (1/4)sinh2x - x/2 + c
integral of cosh is sinh
Ummmm. do you mean sine squared x?
cause idk what the h is doing here.
In order to integrate trig terms with powers, you have to convert them to trig terms without the powers.
In the case of just (sinx)^2 >>
cos2x = 1 - 2(sinx)^2
2(sinx)^2 = 1 - cos2x
(sinx)^2 = 0.5 (1 - cos2x)
Therefore integrating (sinx)^2 is equal to integrating 0.5(1-cos2x)
which is equal to
0.5 (x - 0.5 (sin2x) )
= 0.5x - 0.25sin2x