#### Question

# How to integrate sinh2x ?

how to integrate sinh2x ?

#### Answers

sinh2x = (cosh2x - 1)/2

int of (cosh2x - 1)/2 dx = (1/4)sinh2x - x/2 + c

#1

Cosh(2x)=1+2sinh^2(x)

integral of cosh is sinh

you're done

#2

Ummmm. do you mean sine squared x?

i.e. (sinx)^2?

cause idk what the h is doing here.

In order to integrate trig terms with powers, you have to convert them to trig terms without the powers.

In the case of just (sinx)^2 >>

cos2x = 1 - 2(sinx)^2

2(sinx)^2 = 1 - cos2x

(sinx)^2 = 0.5 (1 - cos2x)

Therefore integrating (sinx)^2 is equal to integrating 0.5(1-cos2x)

which is equal to

0.5 (x - 0.5 (sin2x) )

= 0.5x - 0.25sin2x

#3