# How do i solve this. reduce to the lowest terms a^3+8b^3 / a^2-4b^2?

its the whole first term over the second. pls help

Factor the numerator as the sum of cubes and the denominator as the difference of squares:

a^3 + (2b)^3 = (a + 2b)(a^2 - 2ab + 4b^2)

a^2 - (2b)^2 = (a + 2b)(a - 2b)

You can see the (a + 2b) cancels, and you have

(a^2 - 2ab + 4b^2)/(a - 2b)

And that's as far as you can go.

#1

a^2/(a - 2 b) - 2 b

#2

a^2/(a - 2 b) - 2 b

#3

factor top and bottom

(a + 2b)(a2 - 2ab + 4b2)

---------------------------------- =

(a + 2b)(a - 2b)

cancel common factor

a2 - 2ab + 4b2

---------------------

? ? a - 2b

#4