How do i solve this charles gas law problem?

A soccer ball containing 12.0 L of gas at 21 degrees C is left outside on a cold, winter day. What is the temperature outside in Celsius if the ball shrunk to 10,500 mL?

My answer key says it should be -16 but I cannot seem to get that answer. Please explain how you got -16 and the steps you took. Thank you.


starting with...

V1 / T1 = V2 / T2


T2 = T1 x (V2 / V1)


T2 = (21+273.15) x (10.5L / 12.0L)

T2 = 257.38K = -16°C


did you remember to convert T from °C to K? you must always use an absolute temperature scale when working with gas equations.


I don't know


T(K) = T(°C) + 273.15

ie.. you add 273.15 to get temperature in K

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