Question

What mass of HCl is consumed by the reaction of 3.64 mol of magnesium? (More detail read on please!)?

PART 1)

One reaction that produces hydrogen gas can be represented by the unbalanced chemical equation

Mg(s) + HCl(aq) -----> MgCl2(aq) + H2 (g)

What mass of HCl is consumed by the reaction of 3.64 mol of magnesium? Answer in units of g please!

If you could answer part two and part three too that'd be great! Thanks!

PART 2)

What mass of MgCl2 is produced? Answer in units of g please!

PART 3)

What mass of H2 is produced? Answer in units of g please!

Thank you so much!

Answers

Balance the equation:

Mg + 2HCl --> MgCl2 + H2

Note that 1 mole of Mg consumes 2 mole of HCl and produces 1 mole of MgCl2 and 1 mole of H2.

Moles of HCl = 2 x 3.64 moles of Mg = 7.28 moles of HCl

Moles of MgCl2 = 1 x 3.64 moles of Mg = 3.64 moles of MgCl2

Moles of H2 = 1 x 3.64 moles of Mg = 3.64 moles of H2

7.28 moles of HCl x 36.46 g/mole = 265 g HCl

3.64 moles of MgCl2 x 95.22 g/mole = 347 g MgCl2

3.64 moles of H2 x 2.016 g/mole = 7.34 g H2

#1