Question

3'-T A C G C T T T A G T A G C C A T T-5' Translation (amino acid sequence):?

3'-T A C G C T T T A G T A G C C A T T-5' is a mutated gene sequence how do you find the translation amino acid sequence...what is it?

Answers

1. Transcribe to mRNA, using the base pairing rules, and keeping in mind directionality.

5'-A U G C G A A A U C A U C G G U A A -3'

2. If you can establish "reading frame" then break it up into codons

As you can see, your sequence begins right off the bat with the 5'-AUG start codon, so that's where your reading frame is going to begin.

5'-AUG CGA AAU CAU CGG UAA -3'

3. Look up the codons on a genetic code table (again keeping in mind that the 5' nucleobase is "first"). There's a genetic code table here:

http://en.wikipedia.org/wiki/Genetic_cod…

When you produce your polypeptide sequence, the N (amino) terminus is first, and the carboxyl terminus is last.

http://en.wikipedia.org/wiki/N-terminus

So for your example,

N terminus- Met Arg Asn His Arg -C terminus

Note that the codon 5'-UAA is a STOP codon and is not translated to any amino acid residue.

#1

Just give the opposite.

ATGCGAAATCATCGGTA

#2

convert your seq to the coding strand:

5'atg cga aat cat cgg taa3'

Then look at a "codon table" (<-- google), and see what the codons translate:

atg=Methionine

CGA=arginine

aat=asparagine

cat=histidine

cgg=arginine

taa=stop codon

#3

5'- ATGCGAAATCATCGGTAA - 3'

gives mRNA UAC GCU UUA GUA GCC AUU - these are the codons.

The table showing the amino acids per codon in link.

#4

Just a response to 1 of the 3 Top Contributor's answer

ATG is NOT methionine

AUG = methionine (start codon)

TAA is NOT a stop codon

UAA = stop codon

You got the whole thing WRONG. The process of transcription/translation the T is replaced with Uracil.

......==''

#5