1. Transcribe to mRNA, using the base pairing rules, and keeping in mind directionality.
5'-A U G C G A A A U C A U C G G U A A -3'
2. If you can establish "reading frame" then break it up into codons
As you can see, your sequence begins right off the bat with the 5'-AUG start codon, so that's where your reading frame is going to begin.
5'-AUG CGA AAU CAU CGG UAA -3'
3. Look up the codons on a genetic code table (again keeping in mind that the 5' nucleobase is "first"). There's a genetic code table here:
When you produce your polypeptide sequence, the N (amino) terminus is first, and the carboxyl terminus is last.
So for your example,
N terminus- Met Arg Asn His Arg -C terminus
Note that the codon 5'-UAA is a STOP codon and is not translated to any amino acid residue.
Just give the opposite.
convert your seq to the coding strand:
5'atg cga aat cat cgg taa3'
Then look at a "codon table" (<-- google), and see what the codons translate:
5'- ATGCGAAATCATCGGTAA - 3'
gives mRNA UAC GCU UUA GUA GCC AUU - these are the codons.
The table showing the amino acids per codon in link.
Just a response to 1 of the 3 Top Contributor's answer
ATG is NOT methionine
AUG = methionine (start codon)
TAA is NOT a stop codon
UAA = stop codon
You got the whole thing WRONG. The process of transcription/translation the T is replaced with Uracil.