How to solve 3x2+2√6x+2?

solve by factorization,by completing the square or by quadratic formula but more preferably by factorization

Discriminant = √[(2√6)^2 - 4 * 3 * 2] = 0

=> 3x^2 + 2√6x + 2 is a perfect square and is

= (√3x + √2)^2

An expression cannot be solved. It can be simplified. If you are meaning to solve the equation

3x^2 + 2√6x + 2 =, then its is

(√3x + √2)^2 = 0

=> x = - √(2/3).

#1

[root3x}^2+ 2 X root3x X root2 + [root 2]^2

[Root3x + root 2] ^2

#2

I hope you know your lack of brackets has made this thing unreadable. Does the square root only cover the 6? Does it go all the way to the 2?

#3

In given form , question has no mathematical meaning.

Could there be an = sign somewhere?

Could there be a zero somewhere?

#4

3x2+2√6x+2 =

(x√3 + √2)2

then x = -√2/√3 double root

#5

you put brackets to break down the sum

3x2+2√6x+2

(3x2+2)(√6x+2)

3+2=5+x2=5x2

5x2√8x

because you don't know what x2 is you just have to leave it at that unless in gives you the number for what x2 stands for

i don't know if this is right i am just guessing lol

#6

well .. by looking at it , it tells ..

3x2 = (√3x)2 = a2

2 = (√2)2 = b2

and 2√6 = 2.√3.√2 = 2ab

=> 3x2+2√6x+2 = (√3x + √2)2

==> x= -√(2/3)

NOTE : i did these kinds of sums so i could figure out that it was a whole square by looking at the nos.

bt .. i would suggest you to find out the discriminant (b2-4ac) before solving .. which comes out to be 0 .. indicating it has equal roots .. which means it is a perfect square ! :)

#7