Question
Log of 81 to the base 27?
pls help
Answers
You can rewrite log of 81 to the base of 27 in base 10 by the 'change of base property' as (log81)/(log(27).
log81 = log(3^4) = 4log3 (Using the power rule)
log27 = log(3^3) = 3log3 (Using the power rule)
Therefore, (log81)/(log27) = (4log3)/(3log3) = 4/3
1.33333
http://www.1728.org/logrithm.htm
log 81 =log 81 log 27
27 10 / 10
= 4log 3 3 log 3
10 / 10
= 4/3
=1.333
log of 81 to the base 27 = log81 / log27 =
= log(3^4) / log(3^3) = 4*log3 / 3*log3 =
= 4/3 >==========================< ANSWER
Log A base X = Log A base Y / Log X base Y ........Rule
Therefore, log of 81 to the base 27 = log 81 / log 27 = 1.333333333
Rewrite log of 81 to the base of 27 in base 10 as (log81)/(log(27).
log81 = log(3^4) = 4log3
log27 = log(3^3) = 3log3
So, (log81)/(log27) = (4log3)/(3log3) = 4/3