How do you solve for c=3/4y+b, for y? Or 3ax-n/5=-4, for x?

Please help, I have trouble with these questions.


c = ?y + b; solve for y.

FIRST: subtract b from each side: c-b = ?y+b-b

c-b = ?y

NOTE: to clear fraction in front of the y just multiply bot sides by the reciprocal 4/3

4/3(c-b) = 4/3(?y) becomes 4/3(c-b) = y.


If all left side is over 5 denominator.

(3ax-n)/5 = -4......multiply both sides by 5

5[(3ax-n)/5] = 5(-4) ...... both 5s cancel left side.

3ax-n = -20

3ax-n+n = -20+n

3ax = -20+n

3ax/3a = (-20+n)/3a

x = (-20+n)/3a

Oct 13 at 12:33