Question

Log of 81 to the base 27?

pls help

Answer

You can rewrite log of 81 to the base of 27 in base 10 by the 'change of base property' as (log81)/(log(27).

log81 = log(3^4) = 4log3 (Using the power rule)

log27 = log(3^3) = 3log3 (Using the power rule)

Therefore, (log81)/(log27) = (4log3)/(3log3) = 4/3

Dec 28 at 5:1

1.33333

http://www.1728.org/logrithm.htm

Dec 28 at 8:47

log 81 =log 81 log 27

27 10 / 10

= 4log 3 3 log 3

10 / 10

= 4/3

=1.333

Dec 28 at 12:56

log of 81 to the base 27 = log81 / log27 =

= log(3^4) / log(3^3) = 4*log3 / 3*log3 =

= 4/3 >==========================< ANSWER

Dec 28 at 17:29

Log A base X = Log A base Y / Log X base Y ........Rule

Therefore, log of 81 to the base 27 = log 81 / log 27 = 1.333333333

Dec 28 at 22:24

Rewrite log of 81 to the base of 27 in base 10 as (log81)/(log(27).

log81 = log(3^4) = 4log3

log27 = log(3^3) = 3log3

So, (log81)/(log27) = (4log3)/(3log3) = 4/3

Dec 29 at 3:42