How do i solve this charles gas law problem?
A soccer ball containing 12.0 L of gas at 21 degrees C is left outside on a cold, winter day. What is the temperature outside in Celsius if the ball shrunk to 10,500 mL?
My answer key says it should be -16 but I cannot seem to get that answer. Please explain how you got -16 and the steps you took. Thank you.
V1 / T1 = V2 / T2
T2 = T1 x (V2 / V1)
T2 = (21+273.15) x (10.5L / 12.0L)
T2 = 257.38K = -16°C
did you remember to convert T from °C to K? you must always use an absolute temperature scale when working with gas equations.
I don't know
T(K) = T(°C) + 273.15
ie.. you add 273.15 to get temperature in K