How do you reduce the trinomial (x^2 + 8x + 16) to (x + 4)^2?

sorry, im bad at this.

cause i dont want to do trial and error to get 4.


It's a binomial, not a trinomial.

The way I approach these is, to reduce this to (x+a)(x+b), I need to find a and b such that

a*b = 16


a+b = 8

Since a*b is positive, either both a and b are positive, or both a and b are negative.

Since a+b is positive, a and b must both be positive.

What are the factors of 16? 1 and 16, 2 and 8, 4 and 4. A quick glance reveals which two add up to 8.