#### Question

# East math question! 10 points!?

Math problem: find the length of the diagonal of a 5 by 13cm rectangle.

#### Answers

The diagonal is the hypotenuse of a right angled triangle with legs of 5 & 13, so

d^2 = 5^2 + 13^2 = 25 + 169 = 194

d = √194 ≈ 13.9

lenth=(5^2 + 13^2)^(1/2)=13.93 cm

Just use Pythagorian's Theorem

a^2+b^2=c^2

So...

5^2+13^2=c^2

25+169=194

sqrt 194=13.928

:)

Pythagoras.

C^2 = A^2 + B^2

C is the hypotenuse. A is 5 and B is 13.

C = square root of (25 +169)

C = 13.92838828cm

round to whatever you need.

You need to use the Pythagorean Theorem, a^2 + b^2 = c^2, to solve this problem.

a = 5, b = 13, so 5^2 + 13^2 = c^2.

25 + 169 = c^2

194 = c^2

Take the square root of both sides to get square root of 194 = c.

If you have learned how simplify radical expressions, then you need to go further if possible.

Hope this helps!