# In five years, Tom will be twice as old as cindy. Thirteen years ago, Tom was three times as old as Cindy.?

How many years ago was Tom four times as old as Cindy?

Show Work.

Let Tom's current age be T and Cindy's current age be C.

In 5 years, Tom's age will be (T + 5) and Cindy's age will be (C + 5).

Since in 5 years Tom will be twice as old as Cindy, (T + 5) = 2(C + 5)

So,

T + 5 = 2(C + 5)

T + 5 = 2C + 10

T = 2C + 5 ---> First equation

13 years ago, Tom's age was (T - 13) and Cindy's age was (C - 13).

(T - 13) = 3(C - 13)

T - 13 = 3C - 39

T = 3C - 26 ---> Second equation

Now we solve simultaneously to obtain their current age.

Equate first equation with second equation.

2C + 5 = 3C - 26

2C - 3C = -26 - 5

-C = -31

C = 31

Replace C = 31 in first equation.

T = 2(31) + 5

T = 62 + 5

T = 67

So, currently Tom is 67 years and Cindy is 31.

x years ago, Tom was (67 - x) and Cindy was (31 - x).

x years ago, Tom was 4 times as old as Cindy. Therefore, (67 - x) = 4(31 - x)

Solve for x now and that will be your final answer.

67 - x = 4(31 - x)

67 - x = 124 - 4x

-x + 4x = 124 - 67

3x = 57

x = (57 / 3) = 19

So, 19 years ago, Tom was 4 times as old as Cindy.

Just for verification, 19 years ago, Tom was (67 - 19) and Cindy was (31 - 19).

67 - 19 = 4(31 - 19)

48 = 4(12)

48 = 48 (True)

#1

who would care! i mean, you could just go ask her. >:I

#2

Obviously, Tom is aging faster. Therefore, Tom is an alien, and Cindy is a slut.

#3