We would first start by setting all of our data into a matrix equation, then label each matrice.
A X B
|1 -2 -3||x| |6|
|2 1 -1||y|=|6|
|4 -3 -7||z| |6|
Which gives us the equation AX=B. To solve for X we must multiply A and B by the inverse of A to give us an equation like X=A'B. Since the inverse of A starts by multiplying 1/|A| we should solve for the determinant of A. If it is 0 then there are no solutions.
Therefore there are no solutions for this linear system.
We could also do this algebraically which would give us no solutions.
is this stupid thing from this world?
hey i think i can solve this but is too hard to explain it here .. i am so so so sorry